(-2v^2+v-4)=0

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Solution for (-2v^2+v-4)=0 equation:


Simplifying
(-2v2 + v + -4) = 0

Reorder the terms:
(-4 + v + -2v2) = 0

Remove parenthesis around (-4 + v + -2v2)
-4 + v + -2v2 = 0

Solving
-4 + v + -2v2 = 0

Solving for variable 'v'.

Begin completing the square.  Divide all terms by
-2 the coefficient of the squared term: 

Divide each side by '-2'.
2 + -0.5v + v2 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -0.5v + -2 + v2 = 0 + -2

Reorder the terms:
2 + -2 + -0.5v + v2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -0.5v + v2 = 0 + -2
-0.5v + v2 = 0 + -2

Combine like terms: 0 + -2 = -2
-0.5v + v2 = -2

The v term is v.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-0.5v + 0.25 + v2 = -2 + 0.25

Reorder the terms:
0.25 + -0.5v + v2 = -2 + 0.25

Combine like terms: -2 + 0.25 = -1.75
0.25 + -0.5v + v2 = -1.75

Factor a perfect square on the left side:
(v + 0.5)(v + 0.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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